A) 10 h
B) 80 h
C) 40 h
D) 20 h
Correct Answer: C
Solution :
According to Keplers law \[{{T}^{2}}\propto {{r}^{3}}\] or \[{{5}^{2}}\propto {{r}^{3}}\] ... (i) and \[{{(T)}^{2}}\propto {{(4r)}^{3}}\] ... (ii) From Eqs. (i) and (ii) \[\frac{25}{{{(T)}^{2}}}=\frac{{{r}^{3}}}{64{{r}^{3}}}\] \[T=\sqrt{1600}\] \[=40\,\,h\]You need to login to perform this action.
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