A) 50 Hz
B) 100 Hz
C) 200 Hz
D) 25 Hz
Correct Answer: A
Solution :
The wire will vibrate with the same frequency as that of source. This can be considered as an example of forced vibration. \[T=10\times 9.8N=98N\] \[m=9.8\times {{10}^{-3}}kg/m\] Frequency of wire\[f=\frac{1}{2L}\sqrt{\left( \frac{T}{m} \right)}\] \[=\frac{1}{2\times 1}\sqrt{\left( \frac{98}{9.8\times {{10}^{-3}}} \right)}\] \[=50\,\,Hz\]You need to login to perform this action.
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