A) 300
B) 600
C) 1200
D) 200
Correct Answer: A
Solution :
The given equation of wave, \[y={{10}^{-4}}\sin \left( 600t-2x+\frac{\pi }{3} \right)\] ... (i) Standard equation of wave \[y=a\sin (\omega t-kx+\phi )\] ... (ii) Now comparing Eqs. (i) and (ii), we get, \[\omega =600\]and\[k=2\] \[\therefore \]Velocity of wave\[=\frac{\omega }{k}=\frac{600}{2}=300\,\,m/s\]You need to login to perform this action.
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