A) \[0.07\]
B) \[0.14\]
C) \[0.28\]
D) \[0.35\]
Correct Answer: A
Solution :
Let molarity of\[Ba{{(OH)}_{2}}={{M}_{1}}\] Normality\[=2{{M}_{1}}\] Molarity of\[HCl=0.1M=0.1N\] \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[2{{M}_{1}}\times 25=0.1\times 35\] \[{{M}_{1}}=0.07M\]You need to login to perform this action.
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