A) \[0.02\]
B) \[0.05\]
C) \[0.04\]
D) \[0.07\]
Correct Answer: B
Solution :
Change in oxidation number\[(+7)-(+2)=5\] \[\therefore \]Normality of solution\[=5\times 0.04=0.20\,\,N\] Volume\[=250\,\,mL\] \[\therefore \]Number of equivalents of\[KMn{{O}_{4}}\] \[=0.20\times \frac{250}{1000}=0.05\]You need to login to perform this action.
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