A) \[-0.28\,\,V\]
B) \[-0.34\,\,V\]
C) \[-0.82\,\,V\]
D) \[-0.22\,\,V\]
Correct Answer: A
Solution :
\[E_{cell}^{o}=E_{cell}^{o}-\frac{2.303RT}{nF}\log \left[ \frac{[Ni]}{[N{{i}^{2+}}]} \right]\] \[=-0.25-\frac{0.06}{2}\log \left( \frac{1}{0.1} \right)\] \[(\because \,\,n=2)\] \[=-0.25-0.03\times 1\] \[{{E}_{cell}}=-0.28\,\,V\]You need to login to perform this action.
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