A) \[30{}^\circ \]
B) \[45{}^\circ \]
C) \[60{}^\circ \]
D) \[0{}^\circ \]
Correct Answer: C
Solution :
Key Idea Slope of the path of the particle gives the measure of angle required. Draw the situation as shown. \[OA\] represents the path of the particle starting from origin \[O(0,\,\,0)\]. Draw a perpendicular from point\[A\] to\[x-\]axis. Let path of the particle makes an angle \[\theta \] with the \[x-\]axis, then \[\tan \theta =\]slope of line\[OA\] \[=\frac{AB}{OB}=\frac{3}{\sqrt{3}}=\sqrt{3}\] or \[\theta ={{60}^{o}}\]You need to login to perform this action.
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