RAJASTHAN PMT Rajasthan - PMT Solved Paper-2008

  • question_answer
    When the current changes from +2A to - 2A in 0.05 s, an emf of 8V is induced in a coil. The coefficient of self-induction of the coil is

    A)  0.2 H                                    

    B)  0.4 H

    C)  0.8 H                    

    D)         0.1 H

    Correct Answer: D

    Solution :

    \[e=-L\frac{di}{dt}=-L\frac{(-2-2)}{0.05}\]                 \[8=L\frac{(4)}{0.05}\] \[\therefore \]  \[L=\frac{8\times 0.05}{4}=0.1\,\,H\]


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