A) \[5\times {{10}^{-3}}\,N/m\]
B) \[5\times {{10}^{-2}}\,N/m\]
C) 5 N/m
D) 50 N/m
Correct Answer: B
Solution :
Given,\[r=2\times {{10}^{3}}m.\] \[F=W={{V}_{\rho g}}=6.28\times {{10}^{-4}}m\] Surface tension\[(T)=\frac{F}{2\pi r}=\frac{6.28\times {{10}^{-4}}}{2\times 3.14\times 2\times {{10}^{-3}}}\] \[=0.05N/m=5\times {{10}^{-2}}N/m\]You need to login to perform this action.
You will be redirected in
3 sec