A) 20 W
B) 40 W
C) 1000 W
D) zero
Correct Answer: D
Solution :
\[I=5\sin (100t-\pi /2)\] \[V=200\,\,\sin \,\,100t\] Phase difference between alternating current and alternating voltage is\[n/\text{ }2\]. \[\therefore \]Power consumption\[(\bar{P})={{V}_{rms}}\cdot {{I}_{rms}}\cdot \cos \frac{\pi }{2}\] \[=0\]You need to login to perform this action.
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