A) \[{{10}^{16}}\,Wb/{{m}^{2}}\]
B) \[{{10}^{5}}\,Wb/{{m}^{2}}\]
C) \[{{10}^{3}}\,Wb/{{m}^{2}}\]
D) \[{{10}^{-3}}\,Wb/{{m}^{2}}\]
Correct Answer: C
Solution :
As particle is moving without deviation, therefore \[Eq=Bqv\] \[\therefore \] \[B=\frac{E}{v}=\frac{{{10}^{4}}}{10}\] \[={{10}^{3}}Wb/{{m}^{2}}\]You need to login to perform this action.
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