A) cot \[\theta \]
B) cot \[\theta \]
C) tan \[\theta \]
D) sin \[\theta \]
Correct Answer: C
Solution :
In equilibrium \[T\cos \theta =mg\] ... (i) and \[T=\sin \theta =F=Eq\] \[T\sin \theta =\frac{\sigma }{2{{\varepsilon }_{0}}}\cdot q\] ... (ii) \[\therefore \] \[\frac{T\sin \theta }{T\cos \theta }=\frac{\sigma q}{2{{\varepsilon }_{0}}\times mg}\] \[\tan \theta =\frac{\sigma q}{2{{\varepsilon }_{0}}mg}\] or \[\sigma \propto \tan \theta \]You need to login to perform this action.
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