A) 2
B) 4
C) 3
D) 1
Correct Answer: C
Solution :
Ionization of\[[Co{{(N{{H}_{3}})}_{4}}Cl]C{{l}_{2}}\] is as follows \[[Co{{(N{{H}_{3}})}_{4}}Cl]C{{l}_{2}}{{[Co{{(N{{H}_{3}})}_{4}}Cl]}^{2+}}+2C{{l}^{-}}\]It give three ions.You need to login to perform this action.
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