A) \[3\]
B) \[5\]
C) \[4\]
D) \[2\]
Correct Answer: A
Solution :
The dot structure of \[Xe{{F}_{2}}\] is as follows \[F-:\underset{\centerdot \,\,\centerdot }{\overset{\centerdot \,\,\centerdot }{\mathop{Xe}}}\,-F\] Number of molecular hybrid orbitals = number of sigma bonds + number of lone pair of electrons. \[\therefore \]Number of molecular hybrid orbitals \[=2+3=5\] So, hybridization is\[s{{p}^{3}}d\].You need to login to perform this action.
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