A) 2R
B) R/2
C) 3R
D) 4R
Correct Answer: A
Solution :
If \[R\] is the resistance of the voltmeter and \[I\] current is flowing through it, then \[V=IR\] or \[R=\frac{V}{I}\] If now resistance connected in series is\[R\], then \[R+R=\frac{3V}{I}\] \[R+R=3R\] \[\therefore \] \[R=2R\]You need to login to perform this action.
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