A) 2
B) 3
C) 4
D) 5
Correct Answer: A
Solution :
\[E=\frac{\sigma }{{{\varepsilon }_{0}}}=2.1\times {{10}^{-5}}\] \[E=\frac{\sigma }{{{\varepsilon }_{0}}K}=1\times {{10}^{-5}}\] \[\therefore \] \[\frac{E}{E}=\frac{\sigma }{{{\varepsilon }_{0}}}\times \frac{{{\varepsilon }_{0}}K}{\sigma }=\frac{2.1\times {{10}^{-5}}}{1\times {{10}^{-5}}}\] or \[K=2.1\approx 2\]You need to login to perform this action.
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