A) 1 mH
B) 10 mH
C) 100 mH
D) 1000 mH
Correct Answer: A
Solution :
Induced emf \[e=M\frac{di}{dt}\] \[100\times {{10}^{-3}}=M\left( \frac{10}{0.1} \right)\] \[M={{10}^{-3}}H\] \[M=1mH\]You need to login to perform this action.
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