A) zero
B) \[1\,\mu V\]
C) \[5\,\mu V\]
D) \[10\,\mu V\]
Correct Answer: D
Solution :
Rod is moving towards east, so induced emf across its end will be\[e={{\beta }_{V}}vl=({{B}_{H}}\tan \phi )vl\] \[\therefore \] \[e=3\times {{10}^{-4}}\times \frac{4}{3}\times (10\times {{10}^{-2}})\times 0.25\] \[={{10}^{-5}}V=10\mu V\]You need to login to perform this action.
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