A) 50 W
B) 100 W
C) 200 W
D) 400 W
Correct Answer: D
Solution :
\[\tan \phi =\frac{{{X}_{L}}}{R}=\frac{{{X}_{C}}}{R}\] \[\Rightarrow \] \[\tan {{60}^{o}}=\frac{{{X}_{L}}}{R}=\frac{{{X}_{C}}}{R}\] \[\Rightarrow \] \[{{X}_{L}}={{X}_{C}}=\sqrt{3}R\] \[ie,\] \[Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}=R\] So average power \[P=\frac{{{V}^{2}}}{R}=\frac{200\times 200}{100}=400\,\,W\]You need to login to perform this action.
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