A) \[299.6\,\,K\]
B) \[{{0}^{o}}C\]
C) \[273\,\,K\]
D) \[{{10}^{o}}C\]
Correct Answer: A
Solution :
\[28g{{N}_{2}}=1\,\,mole\]of\[{{N}_{2}}\]. Applying\[pV=nRT\], \[2.46\times 10=1\times 0.0821\times T\]. This gives \[T=299.6\,\,K\]You need to login to perform this action.
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