A) \[C{{H}_{3}}C{{H}_{2}}CH=C{{(C{{H}_{3}})}_{2}}\]
B) \[C{{H}_{3}}C{{H}_{2}}CH=CHC{{H}_{2}}C{{H}_{3}}\]
C) \[C{{H}_{3}}C{{H}_{2}}CH=CHC{{H}_{3}}\]
D) \[{{(C{{H}_{3}})}_{2}}CH=CHC{{H}_{3}}\]
Correct Answer: A
Solution :
\[C{{H}_{3}}C{{H}_{2}}CH=CHC{{H}_{2}}C{{H}_{3}}\] \[\xrightarrow[(ii)Zn/{{H}_{2}}O]{(i){{O}_{3}}}2C{{H}_{3}}C{{H}_{2}}CHO\] \[C{{H}_{3}}C{{H}_{2}}CH=CHC{{H}_{3}}\xrightarrow[(ii)Zn/{{H}_{2}}O]{(i){{O}_{3}}}\] \[C{{H}_{3}}C{{H}_{2}}CHO+C{{H}_{3}}CHO\] \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,=CH-C{{H}_{3}}\xrightarrow[(ii)Zn/{{H}_{2}}O]{(i){{O}_{3}}}\]You need to login to perform this action.
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