A) \[{{H}_{2}}C=CH-C\equiv N\]
B) \[HC\equiv C-C\equiv CH\]
C) \[{{H}_{2}}C=C=C{{H}_{2}}\]
D)
Correct Answer: A
Solution :
(a)\[\underset{s{{p}^{2}}}{\mathop{{{H}_{2}}C}}\,=\underset{s{{p}^{2}}}{\mathop{CH}}\,=\underset{sp}{\mathop{C}}\,\equiv \underset{sp}{\mathop{N}}\,\] (b)\[\underset{sp}{\mathop{HC}}\,\equiv \underset{sp}{\mathop{C}}\,-\underset{sp}{\mathop{C}}\,\equiv \underset{sp}{\mathop{CH}}\,\] (c)\[\underset{s{{p}^{2}}}{\mathop{{{H}_{2}}C}}\,=\underset{sp}{\mathop{C}}\,=\underset{sp}{\mathop{C}}\,=\underset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,\] (d) Hence, \[{{H}_{2}}C=CH-C\equiv N\] represents the \[s{{p}^{2}}-s{{p}^{2}}-sp-sp\]hybridisation from left to right.You need to login to perform this action.
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