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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2010

  • question_answer
    For an equilibrium reaction, the rate constants for the forward and the backward reaction are \[2.38\times {{10}^{-4}}\] and \[8.15\times {{10}^{-5}}\] respectively. What will be the equilibrium constant for the reaction?

    A) \[92.2\]                               

    B)        \[29.2\]

    C)        \[20.2\]                               

    D)        \[2.92\]

    Correct Answer: D

    Solution :

    Equilibrium constant\[K=\frac{{{k}_{f}}}{{{k}_{b}}}\]                                             \[=\frac{2.38\times {{10}^{-4}}}{8.15\times {{10}^{-5}}}\]                                             \[=2.92\]


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