A) \[A\]is ethylene, \[B\] is acetaldehyde
B) \[A\]is acetylene, \[B\] is propionaldehyde
C) \[A\]is ethane, \[B\] is ethanol
D) \[A\]is acetylene, \[B\] is acetaldehyde
Correct Answer: D
Solution :
\[Ca{{C}_{2}}(s)+2{{H}_{2}}O(l)\xrightarrow{{}}\underset{\begin{smallmatrix} (A) \\ \downarrow {{H}_{2}}S{{O}_{4}}/HgS{{O}_{4}} \end{smallmatrix}}{\mathop{HC\equiv CH}}\,+Ca{{(OH)}_{2}}\]\[C{{H}_{3}}-CHOC{{H}_{2}}=\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H\]You need to login to perform this action.
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