A) 4 V
B) 8 V
C) 12 V
D) 16 V
Correct Answer: B
Solution :
Switch \[{{S}_{2}}\] is open so capacitor is not in circuit. Current through \[3\Omega \] resistor\[=\frac{24}{3+3}=4A\] Let potential of point \[O\] shown in figure is \[{{V}_{0}}\] then using Ohms law \[{{V}_{0}}-{{V}_{a}}=3\times 4=12\,\,V\] ... (i) Now, current through \[5\Omega \] resistor\[=\frac{24}{5+1}\] \[=4A\] So \[{{V}_{0}}-{{V}_{b}}=4\times 1=4V\] ... (ii) From Eqs. (i) and (ii), we get \[{{V}_{b}}-{{V}_{a}}=12-4=8\,\,V\]You need to login to perform this action.
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