A) 9.33 cal
B) 10.21 cal
C) 12.67 cal
D) 13.34 cal
Correct Answer: A
Solution :
Work done = Force\[\times \]Displacement \[W=\mu \,\,mg\times (v\times t)\] \[W=(0.2)\times 2\times 9.8\times 2\times 5\] \[W=39.2\,\,J\] Heat generated,\[Q=\frac{W}{J}\] \[=\frac{39.2}{4.2}\] \[=9.33\,\,cal\]You need to login to perform this action.
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