A) \[-\frac{q}{3}\]
B) \[\frac{2q}{3}\]
C) \[q\]
D) \[\frac{4q}{3}\]
Correct Answer: A
Solution :
Initial charge on sphere of radius\[R=q\] Charge on this sphere after joining \[q=\frac{[q+(-2q)]\times R}{R+2R}=\frac{-q\times R}{3R}=-\frac{q}{3}\]You need to login to perform this action.
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