A) 167 V
B) 100 V
C) 625 V
D) 250 V
Correct Answer: C
Solution :
After charging, total charge on the capacitor \[Q=CV\] \[=10\times {{10}^{-6}}F\times 1000\,\,V\] \[={{10}^{-2}}C\] Common potential\[V=\frac{{{C}_{1}}{{V}_{1}}}{{{C}_{1}}+{{C}_{2}}}\] \[=\frac{{{10}^{-2}}}{16\times {{10}^{-6}}}=625\,\,V\]You need to login to perform this action.
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