A) \[{{s}_{2}}=\frac{{{m}_{1}}}{{{m}_{2}}}{{s}_{1}}\]
B) \[{{s}_{2}}=\frac{{{m}_{2}}}{{{m}_{1}}}{{s}_{1}}\]
C) \[{{s}_{2}}=\frac{{{m}_{1}}}{m_{2}^{2}}{{s}_{1}}\]
D) \[{{s}_{2}}=\frac{m_{2}^{1}}{m_{1}^{2}}{{s}_{1}}\]
Correct Answer: C
Solution :
According to the question \[s\propto \frac{1}{{{m}^{2}}}\] \[\therefore \] \[\frac{{{s}_{2}}}{{{s}_{1}}}={{\left( \frac{{{m}_{1}}}{{{m}_{2}}} \right)}^{2}}\] or \[{{s}_{2}}={{\left( \frac{{{m}_{1}}}{{{m}_{2}}} \right)}^{2}}\times {{s}_{1}}\]You need to login to perform this action.
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