A) 450 K
B) 200 K
C) 375 K
D) None of these
Correct Answer: B
Solution :
\[X\propto \frac{1}{T}\] \[\therefore \] \[{{X}_{1}}{{T}_{1}}={{X}_{2}}{{T}_{2}}\] Hence, \[{{T}_{2}}=\frac{1.2\times {{10}^{-5}}\times 300}{1.8\times {{10}^{-5}}}=200\,\,K\]You need to login to perform this action.
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