A) \[\frac{F}{Y(1-\sigma )}\]
B) \[\frac{F}{Y(1+\sigma )}\]
C) \[\frac{F(1-2\sigma )}{Y}\]
D) \[\frac{F}{Y(1+2\sigma )}\]
Correct Answer: C
Solution :
Tensile strain on each face\[=\frac{F}{Y}\] Lateral strain due to the other two forces acting on perpendicular faces\[=\frac{-2\sigma F}{Y}\] Total increase in length\[=(1-2\sigma )\frac{F}{Y}\]You need to login to perform this action.
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