A) \[\sin {{\,}^{-1}}\left( \frac{1}{2\mu } \right)\]
B) \[\sin {{\,}^{-1}}(2\mu )\]
C) \[\cos {{\,}^{-1}}(2\mu )\]
D) \[\cos {{\,}^{-1}}\left( \frac{1}{2\mu } \right)\]
Correct Answer: D
Solution :
By Snells law, \[\mu =\frac{\sin i}{\sin r}\] Here, \[\sin i=\mu \sin 2i\] \[\sin i=2\mu \sin i\cos i\] \[i={{\cos }^{-1}}\left( \frac{1}{2\mu } \right)\]You need to login to perform this action.
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