A) zero
B) \[\frac{qQ}{4\pi {{\varepsilon }_{0}}(\sqrt{2}a)}\]
C) \[\frac{qQ}{4\pi {{\varepsilon }_{0}}(2a)}\]
D) \[\frac{qQ\sqrt{2}a}{4\pi {{\varepsilon }_{0}}}\]
Correct Answer: A
Solution :
\[{{W}_{B\to A}}=Q({{V}_{A}}-{{V}_{B}})\] but \[{{V}_{A}}={{V}_{B}}\] \[\therefore \] \[W=0\]You need to login to perform this action.
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