A) 75 V
B) 50 V
C) 30 V
D) 10 V
Correct Answer: C
Solution :
Given,\[i=2\,\,A,\,\,l=1\,\,m,\,\,A=4\times {{10}^{-9}}{{m}^{2}}\]and\[\rho =6\times {{10}^{-8}}\Omega \text{-}m\] We know that \[V=iR\]and\[R=\frac{\rho l}{A}\] \[V=i\times \frac{\rho l}{A}\] \[V=\frac{2\times 6\times {{10}^{-8}}\times 1}{4\times {{10}^{-9}}}\] \[V=30\,\,volt\]You need to login to perform this action.
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