A) \[2\,m/{{s}^{2}}\]
B) \[4\,m/{{s}^{2}}\]
C) \[8\,m/{{s}^{2}}\]
D) \[10\,m/{{s}^{2}}\]
Correct Answer: D
Solution :
Given,\[x=0.5{{t}^{3}}+2{{t}^{2}}\] and \[t=2s\] \[v=\frac{dx}{dt}=0.5\times 3{{t}^{2}}+4t\] \[a=\frac{{{d}^{2}}x}{d{{t}^{2}}}=1.5\times 2t+4\] \[a=3\times 2+4\] \[(\because \,\,t=2s)\] \[a=10\,\,m/{{s}^{2}}\]You need to login to perform this action.
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