A) T
B) \[\text{T/}\sqrt{\text{2}}\]
C) T/2
D) zero
Correct Answer: C
Solution :
We know that \[T=\frac{1}{2}m{{u}^{2}}\] then, \[KE=\frac{1}{2}m{{\left( \frac{u}{\sqrt{2}} \right)}^{2}}\] \[\theta ={{45}^{o}}\] \[KE=\frac{1}{2}T\]You need to login to perform this action.
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