A) \[2.67\times {{10}^{8}}m/s\]
B) \[~2.25\times {{10}^{8}}\text{ }m/s\]
C) \[1.78\times {{10}^{8}}\text{ }m/s\]
D) \[1.50\times {{10}^{8}}\text{ }m/s\]
Correct Answer: B
Solution :
\[_{a}{{\mu }_{g}}=\frac{{{V}_{a}}}{{{V}_{g}}}\] \[\Rightarrow \] \[\frac{3}{2}=\frac{{{V}_{a}}}{2\times {{10}^{8}}}\Rightarrow {{V}_{a}}=3\times {{10}^{8}}m/s\] \[\Rightarrow \] \[\frac{4}{3}=\frac{3\times {{10}^{8}}}{{{V}_{w}}}\] \[\Rightarrow \] \[{{V}_{w}}=\frac{9}{4}\times {{10}^{8}}=2.25\times {{10}^{8}}\] \[_{a}{{\mu }_{g}}=\frac{{{V}_{a}}}{{{V}_{g}}}\] \[\Rightarrow \] \[\frac{3}{2}=\frac{{{V}_{a}}}{2\times {{10}^{8}}}\Rightarrow {{V}_{a}}=3\times {{10}^{8}}m/s\] \[\Rightarrow \] \[\frac{4}{3}=\frac{3\times {{10}^{8}}}{{{V}_{w}}}\] \[\Rightarrow \] \[{{V}_{w}}=\frac{9}{4}\times {{10}^{8}}=2.25\times {{10}^{8}}\]You need to login to perform this action.
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