A) 132
B) 128
C) 124
D) 126
Correct Answer: B
Solution :
Let these two consecutive even number be x and\[x+2\]. Therefore, \[x(x+2)=16128\] \[\Rightarrow \] \[{{x}^{2}}+2x-16128=0\] \[\Rightarrow \] \[{{x}^{2}}+128x-126x-16128=0\] \[\Rightarrow \] \[x(x+128)-126(x+128)=0\] \[\Rightarrow \] \[x(x+128)-126(x+126)=0\] Since, \[x+128=0\]is not possible. Therefore, \[x-126=0\Rightarrow x=126\] So, the larger number = 128You need to login to perform this action.
You will be redirected in
3 sec