A) \[\frac{7}{15}\]
B) \[\frac{2}{15}\]
C) \[\frac{8}{15}\]
D) \[\frac{5}{7}\]
Correct Answer: A
Solution :
Let the original fraction \[=\frac{x}{y}\] According to the questions, \[\frac{x+x\times 200%}{y+y\times 160%}=\frac{7}{13}\] \[\Rightarrow \] \[\frac{x+\frac{200x}{100}}{\frac{160y}{100}}=\frac{7}{13}\Rightarrow \frac{3x}{2.6y}=\frac{7}{13}\] \[\Rightarrow \] \[\frac{x}{y}=\frac{7}{13}\times \frac{26}{30}=\frac{7}{15}\] Hence, the original fraction is\[\frac{7}{15}\].You need to login to perform this action.
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