A) \[0.2\]tesla
B) \[0.8\]tesla
C) \[0.1\]tesla
D) \[1.6\]tesla
Correct Answer: A
Solution :
\[B=\frac{{{\mu }_{0}}i}{2\pi r}\Rightarrow 0.4=\frac{{{\mu }_{0}}i}{2\pi r}\] \[B'=\frac{{{\mu }_{0}}i}{2\pi (2r)}=\frac{1}{2}\frac{{{\mu }_{0}}i}{2\pi r}=\frac{1}{2}\times 0.4=0.2\]teslaYou need to login to perform this action.
You will be redirected in
3 sec