Railways RRB (Assistant Loco Pilot & Technician) Solved Paper-2 (2014)

  • question_answer
    If the length of second's pendulum is decreased by 2%, how many seconds it will lose per day?

    A)   216s                          

    B)  432s

    C)  864s              

    D)  1728s

    Correct Answer: C

    Solution :

    \[T=2\pi \sqrt{\frac{l}{g}},T'=2\pi \sqrt{\frac{98l}{100g}}\] \[\frac{T'}{T}=\sqrt{\frac{98}{100}}={{\left( 1-\frac{2}{100} \right)}^{\frac{1}{2}}}=\left( 1-\frac{1}{100} \right)\]by binomial theorem. \[\frac{1}{100}=\frac{T-T'}{T}=\]Change in time per second Change per day = Change in 86400 s             \[=\frac{86400\times 1}{100}=864s\]


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