A) 52/55
B) 3/55
C) 41/44
D) 3/44
Correct Answer: B
Solution :
Required Probability \[=\frac{({{5}_{{{C}_{1}}}}+{{4}_{{{C}_{1}}}}+{{3}_{{{C}_{1}}}})}{{{12}_{{{C}_{3}}}}}\] \[\frac{=(5+4+3)}{220}=\frac{12}{220}=\frac{3}{55}\]You need to login to perform this action.
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