A) \[91\sqrt{3}\]meters
B) \[91\sqrt{3}\] meters
C) \[58\sqrt{3}\] meters
D) \[15\sqrt{3}\] meters
Correct Answer: C
Solution :
In\[\Delta ADE\] \[\tan \,\,60{}^\circ =\frac{88.2-1.2}{AE}\] \[\sqrt{3}=\frac{87}{AE}\] \[\Rightarrow \] \[AE=\frac{87}{\sqrt{3}}\] And in\[\Delta AFH\] \[\tan \,\,30{}^\circ =\frac{88.2-1.2}{AH}\] \[\frac{1}{\sqrt{3}}=\frac{87}{AH}\] \[AH=87\sqrt{3}\] Now, the distance travelled by the balloon in this interval \[=AH-AE\] \[=BG-BC\] \[=87\sqrt{3}-\frac{87}{\sqrt{3}}\] \[=\frac{87[3-1]}{\sqrt{3}}\] \[=\frac{87\times 2}{\sqrt{3}}\times \frac{\sqrt{3}}{\sqrt{3}}\] \[=\frac{174\times \sqrt{3}}{3}\] \[=58\sqrt{3\,\,meters}\]You need to login to perform this action.
You will be redirected in
3 sec