A) Sometime true sometime false
B) False
C) True
D) Can't be explained
Correct Answer: C
Solution :
Let the height of the tall building is 100 metres and that of first floor is 10 metres Formula: \[{{v}^{2}}={{u}^{2}}+2gh\] For top of the building, \[{{v}^{2}}_{1}={{0}^{2}}+2\times 10\times 100(\because g=10m/{{s}^{2}})\] \[\Rightarrow \] \[{{v}_{1}}=10\times \sqrt{20}\,\,m/s\] For the first floor, \[{{v}^{2}}_{2}=0+2\times 10\times 10\] \[\Rightarrow \] \[{{v}_{2}}=10\times \sqrt{2}\,\,m/s\] Thus, \[{{v}_{1}}>{{v}_{2}}\]
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