A) 1, 1
B) \[1,\,\,-1\]
C) \[-1,\,1\]
D) \[-1,\,\,-1\]
Correct Answer: A
Solution :
If \[{{(x+y-2)}^{2}}+{{(3x-2y-1)}^{2}}=0\] Then,\[x+y-2=0\] ...(1) \[3x-2y-1=0\] ...(2) On solving eqn. (1) and (2) \[x=+1,\,\,y=+1\]You need to login to perform this action.
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