A) 2.5 Hours
B) 3 Hours
C) 3.5 Hours
D) 4 Hours
Correct Answer: B
Solution :
A pipe discharging 10 litre/sec.can fill a mild-height tank in 1 hour. Now, capacity of a tank \[=2\times 60\times 60\times 10\,\,litre\] \[=72000\,\,litre\] Then, remaing half tank of capacity 36000 litre will fill in \[\frac{36000}{(10-5)\times 60\times 60}=\frac{36000}{5\times 60\times 60}\] \[=2\,\,hour\] Hence, required total time=1+2 =3 hoursYou need to login to perform this action.
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