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Railways R.R.C. (Gorakhpur) Solved Paper Held on 2nd Shift 30-11-2014

  • question_answer
    \[{{x}^{2}}-16x+64=0\], what is the value of\[{{x}^{2}}\]?

    A) 8                                 

    B) 16

    C) 64                                

    D) 4

    Correct Answer: C

    Solution :

    \[{{x}^{2}}-16x+64=0\]                  \[{{(x-8)}^{2}}=0\]                   \[x-8=0\]                   \[x=8\]                    \[{{x}^{2}}={{8}^{2}}=64\]                            


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