A) 7
B) 9
C) 5
D) 3
Correct Answer: A
Solution :
Suppose the number is x. Then, \[x-4=\frac{1}{x}\times 21\] \[{{x}^{2}}-4x-21=0\] \[{{x}^{2}}-7x+3x-21=0\] \[(x-7)\,\,(x+3)=0\] \[x=7\]You need to login to perform this action.
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