A) 1860
B) 1890
C) 1845
D) 1677
Correct Answer: C
Solution :
A, B, C, D are four consecutive odd integers. Then__ B = A+2 C = A+4 D = A+6 According to question? \[\frac{A+B+C+D}{4}=42\] \[\frac{4A+12}{4}=42\] \[A+3=42\] \[A=39\] Hence, product of B and D = (39+2) (39+6) = 41 \[\times \] 45 = 1845You need to login to perform this action.
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