A) 10
B) 12
C) 14
D) 16
Correct Answer: C
Solution :
Three pipes can fill a tank in 1 hour =\[\frac{1}{6}\] Then, After 2 hour. tank will fill\[=\frac{2}{6}=\frac{1}{3}\] Remaining part of tank \[=1-\frac{1}{3}=\frac{2}{3}\] Now, A and B can fill the \[\frac{2}{3}\]part in 7 hour then A and B will fill the tank in 1 hour\[=\frac{2}{3\times 7}=\frac{2}{21}\]part Hence, Pipe C will fill the tank in 1 hour \[=\frac{1}{6}-\frac{2}{21}\] \[=\frac{1}{14}part\] Now, Pipe C alone to fill the tank in 14 hours.You need to login to perform this action.
You will be redirected in
3 sec